Finding outer products of vectors - Python Vs Julia
Python
import numpy as np
a = np.array([1, 2])
b = np.array([3, 4])
np.outer(a, b)
Output
array([[3, 4],
[6, 8]])
Julia
a = [1, 2]
b = [3, 4]
a * b'
Output
2×2 Matrix{Int64}:
3 4
6 8
Python
import numpy as np
a = np.array([1, 2])
b = np.array([3, 4])
np.outer(a, b)
Output
array([[3, 4],
[6, 8]])
Julia
a = [1, 2]
b = [3, 4]
a * b'
Output
2×2 Matrix{Int64}:
3 4
6 8