Testing Mathjax on my blog
When a≠0, there are two solutions to ax2+bx+c=0 and they are
x=−b±√b2−4ac2a.Euler is beautiful:
eiπ+1=0When a≠0, there are two solutions to ax2+bx+c=0 and they are
x=−b±√b2−4ac2a.Euler is beautiful:
eiπ+1=0